1Z0-803 New Test Bootcamp - Oracle Latest Java SE 7 Programmer I Test Pattern - Omgzlook

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1Z0-803 PDF DEMO:

QUESTION NO: 1
Given:
What is the result?
A. 0 Done
B. First Exception Done
C. Second Exception
D. Done Third Exception
E. Third Exception
Answer: E

QUESTION NO: 2
Given the code fragment:
A. Super Sub Sub
B. Contract Contract Super
C. Compilation fails at line n1
D. Compilation fails at line n2
Answer: A

QUESTION NO: 3
Given the code fragment:
What is the result?
A. 3 false 1
B. 2 true 3
C. 2 false 3
D. 3 true 1
E. 3 false 3
F. 2 true 1
G. 2 false 1
Answer: D
Explanation:
The length of the element with index 0, {0, 1, 2}, is 3. Output: 3 The element with index 1, {3, 4, 5, 6}, is of type array. Output: true The element with index 0, {0, 1, 2} has the element with index 1: 1.
Output: 1

QUESTION NO: 4
Given:
Which two are possible outputs?
A. Option A
B. Option B
C. Option C
D. Option D
Answer: A,D
Explanation:
The first println statement, System.out.println("Before if clause");, will always run.
If Math.Random() > 0.5 then there is an exception. The exception message is displayed and the program terminates.
If Math.Random() > 0.5 is false, then the second println statement runs as well.

QUESTION NO: 5
Which three are advantages of the Java exception mechanism?
A. Improves the program structure because the error handling code is separated from the normal program function
B. Provides a set of standard exceptions that covers all the possible errors
C. Improves the program structure because the programmer can choose where to handle exceptions
D. Improves the program structure because exceptions must be handled in the method in which they occurred
E. allows the creation of new exceptions that are tailored to the particular program being
Answer: A,C,E
Explanation:
A: The error handling is separated from the normal program logic.
C: You have some choice where to handle the exceptions.
E: You can create your own exceptions.

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Updated: May 28, 2022