1Z0-047 Latest Test Discount & Oracle 1Z0-047 Complete Exam Dumps - Oracle Database SQL Expert - Omgzlook

We are sure you can seep great deal of knowledge from our 1Z0-047 Latest Test Discount study prep in preference to other materials obviously. Our 1Z0-047 Latest Test Discount practice materials have variant kinds including PDF, app and software versions. As 1Z0-047 Latest Test Discount exam questions with high prestige and esteem in the market, we hold sturdy faith for you. With easy payment and thoughtful, intimate after-sales service, believe that our 1Z0-047 Latest Test Discount exam dumps will not disappoint users. Last but not least, our worldwide service after-sale staffs will provide the most considerable and comfortable feeling for you in twenty -four hours a day, as well as seven days a week incessantly. And our professionals always keep a close eye on the new changes of the subject and keep updating the 1Z0-047 Latest Test Discount study questions to the most accurate.

Our 1Z0-047 Latest Test Discount study materials deserve your purchasing.

Other Oracle Certification 1Z0-047 Latest Test Discount - Oracle Database SQL Expert If you find any problems during use, you can give us feedback. A free trial service is provided for all customers by our Valid 1Z0-047 Test Pattern study quiz, whose purpose is to allow customers to understand our products in depth before purchase. Many students often complain that they cannot purchase counseling materials suitable for themselves.

This shows what? As long as you use our products, you can pass the exam! Do you want to be one of 99? Quickly purchase our 1Z0-047 Latest Test Discount exam questions! And you will find that the coming exam is just a piece of cake in front of you.

Oracle 1Z0-047 Latest Test Discount - I hope we have enough sincerity to impress you.

Do you want to get a better job or a higher income? If the answer is yes, then you should buy our 1Z0-047 Latest Test Discount exam questions for our 1Z0-047 Latest Test Discount study materials can help you get what you want. Go against the water and retreat if you fail to enter. The pressure of competition is so great now. If you are not working hard, you will lose a lot of opportunities! There is no time, quickly purchase 1Z0-047 Latest Test Discount study materials, pass the exam! Come on!

If you don't believe, you can give it a try. The passing rate is the best test for quality of our 1Z0-047 Latest Test Discount study materials.

1Z0-047 PDF DEMO:

QUESTION NO: 1
Evaluate the following CREATE SEQUENCE statement: CREATE SEQUENCE seq1 START WITH 100
INCREMENT BY 10 MAXVALUE 200 CYCLE NOCACHE; The sequence SEQ1 has generated numbers up to the maximum limit of 200. You issue the following SQL statement: SELECT seq1.nextval FROM dual; What is displayed by the SELECT statement?
A.1
B.10
C.100
D.an error
Answer:A

QUESTION NO: 2
View the Exhibit and examine the description of the EMPLOYEES table. Your company decided to give a monthly bonus of $50 to all the employees who have completed five years in the company. The following statement is written to display the LAST_NAME, DEPARTMENT_ID, and the total annual salary:
SELECT last_name, department_id, salary+50*12 "Annual Compensation" FROM employees WHERE
MONTHS_BETWEEN(SYSDATE, hire_date)/12 >= 5; When you execute the statement, the "Annual
Compensation" is not computed correctly. What changes would you make to the query to calculate the annual compensation correctly?
A.Change the SELECT clause to SELECT last_name, department_id, salary*12+50 "Annual
Compensation".
B.Change the SELECT clause to SELECT last_name, department_id, salary+(50*12) "Annual
Compensation".
C.Change the SELECT clause to SELECT last_name, department_id, (salary+50)*12 "Annual
Compensation".
D.Change the SELECT clause to SELECT last_name, department_id, (salary*12)+50 "Annual
Compensation".
Answer:C

QUESTION NO: 3
View the Exhibit and examine the description of the EMPLOYEES table. You want to display the
EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT_ID for all the employees who work in the same department and have the same manager as that of the employee having EMPLOYEE_ID 104. To accomplish the task, you execute the following SQL statement: SELECT employee_id, first_name, department_id FROM employees WHERE (manager_id, department_id) =(SELECT department_id, manager_id FROM employees WHERE employee_id = 104) AND employee_id <> 104; When you execute the statement it does not produce the desired output. What is the reason for this?
A.The WHERE clause condition in the main query is using the = comparison operator, instead of EXISTS.
B.The WHERE clause condition in the main query is using the = comparison operator, instead of the IN operator.
C.The WHERE clause condition in the main query is using the = comparison operator, instead of the =
ANY operator.
D.The columns in the WHERE clause condition of the main query and the columns selected in the subquery should be in the same order.
Answer:D

QUESTION NO: 4
View the Exhibit and examine the descriptions of ORDER_ITEMS and ORDERS tables. You want to display the CUSTOMER_ID, PRODUCT_ID, and total (UNIT_PRICE multiplied by QUANTITY) for the order placed. You also want to display the subtotals for a CUSTOMER_ID as well as for a PRODUCT_ID for the last six months. Which SQL statement would you execute to get the desired output?
A.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
B.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) HAVING
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
C.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id, oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) >= 6;
D.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id WHERE MONTHS_BETWEEN(order_date, SYSDATE) <= 6
GROUP BY ROLLUP (o.customer_id, oi.product_id) ;
Answer:D

QUESTION NO: 5
View the Exhibit and examine the description of the ORDERS table. Which two WHERE clause conditions demonstrate the correct usage of conversion functions? (Choose two.)
A.WHERE order_date > TO_DATE('JUL 10 2006','MON DD YYYY')
B.WHERE TO_CHAR(order_date,'MON DD YYYY') = 'JAN 20 2003'
C.WHERE order_date > TO_CHAR(ADD_MONTHS(SYSDATE,6),'MON DD YYYY')
D.WHERE order_date IN ( TO_DATE('Oct 21 2003','Mon DD YYYY'), TO_CHAR('NOV 21 2003','Mon DD
YYYY') )
Answer:A B

We introduce a free trial version of the ACFE CFE learning guide because we want users to see our sincerity. The one who choose our study materials that consider our website as the top preparation material seller for Microsoft SC-900 study materials, and inevitable to carry all candidates the finest knowledge on exam syllabus contents. The existence of our Huawei H28-111_V1.0 learning guide is regarded as in favor of your efficiency of passing the exam. Microsoft AZ-900 - Most importantly, these continuously updated systems are completely free to users. ISACA CISA-CN - And we will send you the new updates if our experts make them freely.

Updated: May 27, 2022