1Z0-051 Lab Questions & Exam 1Z0-051 Tutorials - Oracle Sample 1Z0-051 Questions Pdf - Omgzlook

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1Z0-051 PDF DEMO:

QUESTION NO: 1
Top N analysis requires _____ and _____. (Choose two.)
A. the use of rowid
B. a GROUP BY clause
C. an ORDER BY clause
D. only an inline view
E. an inline view and an outer query
Answer: C,E
Explanation:
The correct statement for Top-N Analysis
SELECT [coloumn_list], ROWNUM
FROM (SELECT [coloumn_list]
FROM table
ORDER BY Top-N_coloumn)
WHERE ROWNUM <= N;
Incorrect answer:
AROWID is not require
BGROUP BY clause is not require
DMust have inline view and outer query.
Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 11-23

QUESTION NO: 2
Which three statements are true regarding sub queries? (Choose three.)
A. Multiple columns or expressions can be compared between the main query and sub query
B. Main query and sub query can get data from different tables
C. Sub queries can contain GROUP BY and ORDER BY clauses
D. Main query and sub query must get data from the same tables
E. Sub queries can contain ORDER BY but not the GROUP BY clause
F. Only one column or expression can be compared between the main query and subqeury
Answer: A,B,C

QUESTION NO: 3
Examine the data in the CUST_NAME column of the CUSTOMERS table.
CUST_NAME
Lex De Haan
Renske Ladwig
Jose Manuel Urman
Jason Mallin
You want to extract only those customer names that have three names and display the * symbol in place of the
first name as follows:
CUST NAME
*** De Haan
**** Manuel Urman
Which two queries give the required output? (Choose two.)
A.SELECT LPAD(SUBSTR(cust_name,INSTR(cust_name,' ')),LENGTH(cust_name),'*')
"CUST NAME" FROM customers
WHERE INSTR(cust_name, ' ',1,2)<>0;
B.SELECT LPAD(SUBSTR(cust_name,INSTR(cust_name,' ')),LENGTH(cust_name),'*')
"CUST NAME" FROM customers
WHERE INSTR(cust_name, ' ',-1,2)<>0;
C.SELECT LPAD(SUBSTR(cust_name,INSTR(cust_name,' ')),LENGTH(cust_name)-
INSTR(cust_name,''),'*') "CUST NAME"
FROM customers
WHERE INSTR(cust_name, ' ',-1,-2)<>0;
D.SELECT LPAD(SUBSTR(cust_name,INSTR(cust_name,' ')),LENGTH(cust_name)-
INSTR(cust_name,' '),'*') "CUST NAME"
FROM customers
WHERE INSTR(cust_name, ' ',1,2)<>0 ;
Answer: A,B

QUESTION NO: 4
You own a table called EMPLOYEES with this table structure:
EMPLOYEE_ID NUMBER Primary Key
FIRST_NAME VARCHAR2(25)
LAST_NAME VARCHAR2(25)
HIRE_DATE DATE
What happens when you execute this DELETE statement?
DELETE employees;
A. You get an error because of a primary key violation.
B. The data and structure of the EMPLOYEES table are deleted.
C. The data in the EMPLOYEES table is deleted but not the structure.
D. You get an error because the statement is not syntactically correct.
Answer: C
Explanation:
Explanation:
You can remove existing rows from a table by using the DELETE statement. DELETE [FROM] table
[WHEREcondition]; Incorrect
answer: AStatement
will not cause error BDelete statement will not delete the table structure DStatement will not cause error
Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 8-19

QUESTION NO: 5
Which SQL statement displays the date March 19, 2001 in a format that appears as
"Nineteenth of March 2001 12:00:00 AM"?
A. SELECT TO_CHAR(TO_DATE('19-Mar-2001', 'DD-Mon-YYYY'), 'fmDdspth "of" Month YYYY fmHH:MI:SS AM') NEW_DATE FROM dual;
B. SELECT TO_CHAR(TO_DATE('19-Mar-2001', 'DD-Mon-YYYY'), 'Ddspth "of" Month YYYY fmHH:MI:SS
AM') NEW_DATE FROM dual;
C. SELECT TO_CHAR(TO_DATE('19-Mar-2001', 'DD-Mon-YYYY'), 'fmDdspth "of" Month YYYY HH:MI:SS
AM') NEW_DATE FROM dual;
D. SELECT TO_CHAR(TO_DATE('19-Mar-2001', 'DD-Mon-YYYY), 'fmDdspth "of" Month
YYYYfmtHH:HI:SS AM') NEW_DATE FROM dual;
Answer: A

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Updated: May 27, 2022