310-083 Simulator & Sun 310-083 Test Score Report - Sun Certified Web Component Developer For J2EE 5 - Omgzlook

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310-083 PDF DEMO:

QUESTION NO: 1
Assume that a news tag library contains the tags lookup and item: lookup Retrieves the latest news headlines and executes the tag body once for each headline. Exposes a NESTED page-scoped attribute called headline of type com.example.Headline containing details for that headline.
item Outputs the HTML for a single news headline. Accepts an attribute info of type com.example.Headline containing details for the headline to be rendered.Which snippet of JSP code returns the latest news headlines in an HTML table, one per row?
A. <table>
<tr>
<td>
<news:lookup />
<news:item info="${headline}" />
</td>
</tr>
</table>
B. <news:lookup />
<table>
<tr>
<td><news:item info="${headline}" /></td>
</tr>
</table>
C. <table>
<news:lookup>
<tr>
<td><news:item info="${headline}" /></td>
</tr>
</news:lookup>
</table>
D. <table>
<tr>
<news:lookup>
<td><news:item info="${headline}" /></td>
</news:lookup>
</tr>
</table>
Answer: C

QUESTION NO: 2
One of the use cases in your web application uses many session-scoped attributes. At the end of the use case, you want to clear out this set of attributes from the session object. Assume that this static variable holds this set of attribute names:
201. private static final Set<String> USE_CASE_ATTRS;
202. static {
203. USE_CASE_ATTRS.add("customerOID");
204. USE_CASE_ATTRS.add("custMgrBean");
205. USE_CASE_ATTRS.add("orderOID");
206. USE_CASE_ATTRS.add("orderMgrBean");
207. }
Which code snippet deletes these attributes from the session object?
A. session.removeAll(USE_CASE_ATTRS);
B. for ( String attr : USE_CASE_ATTRS ) {
session.remove(attr);
}
C. for ( String attr : USE_CASE_ATTRS ) {
session.removeAttribute(attr);
}
D. for ( String attr : USE_CASE_ATTRS ) {
session.deleteAttribute(attr);
}
E. session.deleteAllAttributes(USE_CASE_ATTRS);
Answer: C

QUESTION NO: 3
Which statement is true about web container session management?
A. Access to session-scoped attributes is guaranteed to be thread-safe by the web container.
B. To activate URL rewriting, the developer must use the HttpServletResponse.setURLRewriting method.
C. If the web application uses HTTPS, then the web container may use the data on the HTTPS request stream to identify the client.
D. The JSESSIONID cookie is stored permanently on the client so that a user may return to the web application and the web container will rejoin that session.
Answer: C

QUESTION NO: 4
Which JSTL code snippet can be used to perform URL rewriting?
A. <a href='<c:url url="foo.jsp"/>' />
B. <a href='<c:link url="foo.jsp"/>' />
C. <a href='<c:url value="foo.jsp"/>' />
D. <a href='<c:link value="foo.jsp"/>' />
Answer: C

QUESTION NO: 5
As a convenience feature, your web pages include an Ajax request every five minutes to a special servlet that monitors the age of the user's session. The client-side JavaScript that handles the Ajax callback displays a message on the screen as the session ages. The Ajax call does NOT pass any cookies, but it passes the session ID in a request parameter called sessionID. In addition, assume that your webapp keeps a hashmap of session objects by the ID. Here is a partial implementation of this servlet:
10. public class SessionAgeServlet extends HttpServlet {
11. public void service(HttpServletRequest request, HttpServletResponse) throws IOException {
12. String sessionID = request.getParameter("sessionID");
13. HttpSession session = getSession(sessionID);
14. long age = // your code here
15. response.getWriter().print(age);
16. } ... // more code here
47. }
Which code snippet on line 14, will determine the age of the session?
A. session.getMaxInactiveInterval();
B. session.getLastAccessed().getTime() - session.getCreationTime().getTime();
C. session.getLastAccessedTime().getTime() - session.getCreationTime().getTime();
D. session.getLastAccessed() - session.getCreationTime();
E. session.getMaxInactiveInterval() - session.getCreationTime();
F. session.getLastAccessedTime() - session.getCreationTime();
Answer: F

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Updated: May 26, 2022