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1Z0-047 PDF DEMO:
QUESTION NO: 1
View the Exhibit and examine the description of the EMPLOYEES table. You want to display the
EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT_ID for all the employees who work in the same department and have the same manager as that of the employee having EMPLOYEE_ID 104. To accomplish the task, you execute the following SQL statement: SELECT employee_id, first_name, department_id FROM employees WHERE (manager_id, department_id) =(SELECT department_id, manager_id FROM employees WHERE employee_id = 104) AND employee_id <> 104; When you execute the statement it does not produce the desired output. What is the reason for this?
A.The WHERE clause condition in the main query is using the = comparison operator, instead of EXISTS.
B.The WHERE clause condition in the main query is using the = comparison operator, instead of the IN operator.
C.The WHERE clause condition in the main query is using the = comparison operator, instead of the =
ANY operator.
D.The columns in the WHERE clause condition of the main query and the columns selected in the subquery should be in the same order.
Answer:D
QUESTION NO: 2
Evaluate the following CREATE SEQUENCE statement: CREATE SEQUENCE seq1 START WITH 100
INCREMENT BY 10 MAXVALUE 200 CYCLE NOCACHE; The sequence SEQ1 has generated numbers up to the maximum limit of 200. You issue the following SQL statement: SELECT seq1.nextval FROM dual; What is displayed by the SELECT statement?
A.1
B.10
C.100
D.an error
Answer:A
QUESTION NO: 3
View the Exhibit and examine the descriptions of ORDER_ITEMS and ORDERS tables. You want to display the CUSTOMER_ID, PRODUCT_ID, and total (UNIT_PRICE multiplied by QUANTITY) for the order placed. You also want to display the subtotals for a CUSTOMER_ID as well as for a PRODUCT_ID for the last six months. Which SQL statement would you execute to get the desired output?
A.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
B.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) HAVING
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
C.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id, oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) >= 6;
D.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id WHERE MONTHS_BETWEEN(order_date, SYSDATE) <= 6
GROUP BY ROLLUP (o.customer_id, oi.product_id) ;
Answer:D
QUESTION NO: 4
View the Exhibit and examine the description of the EMPLOYEES table. Your company decided to give a monthly bonus of $50 to all the employees who have completed five years in the company. The following statement is written to display the LAST_NAME, DEPARTMENT_ID, and the total annual salary:
SELECT last_name, department_id, salary+50*12 "Annual Compensation" FROM employees WHERE
MONTHS_BETWEEN(SYSDATE, hire_date)/12 >= 5; When you execute the statement, the "Annual
Compensation" is not computed correctly. What changes would you make to the query to calculate the annual compensation correctly?
A.Change the SELECT clause to SELECT last_name, department_id, salary*12+50 "Annual
Compensation".
B.Change the SELECT clause to SELECT last_name, department_id, salary+(50*12) "Annual
Compensation".
C.Change the SELECT clause to SELECT last_name, department_id, (salary+50)*12 "Annual
Compensation".
D.Change the SELECT clause to SELECT last_name, department_id, (salary*12)+50 "Annual
Compensation".
Answer:C
QUESTION NO: 5
View the Exhibit and examine the structure of the EMPLOYEES table. You want to retrieve hierarchical data of the employees using the top-down hierarchy. Which SQL clause would let you choose the direction to walk through the hierarchy tree?
A.WHERE
B.HAVING
C.GROUP BY
D.START WITH
E.CONNECT BY PRIOR
Answer:E
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Updated: May 27, 2022