1Z0-047 Exams - Oracle New Oracle Database SQL Expert Test Notes - Omgzlook

Our 1Z0-047 Exams study materials boost superior advantages and the service of our products is perfect. We choose the most useful and typical questions and answers which contain the key points of the test and we try our best to use the least amount of questions and answers to showcase the most significant information. Our 1Z0-047 Exams learning guide provides a variety of functions to help the clients improve their learning. Indeed, Oracle 1Z0-047 Exams test is very difficult exam, but this is not suggested that you cannot get high marks and pass your exam with ease. Without knowing the shortcut of Oracle 1Z0-047 Exams exam, do you want to know the testing technique? As for the point, I can tell you that Omgzlook Oracle 1Z0-047 Exams study guide is your unique choice. No matter in the day or on the night, you can consult us the relevant information about our 1Z0-047 Exams preparation exam through the way of chatting online or sending emails.

Other Oracle Certification 1Z0-047 Don't worry over trifles.

In addition, the 1Z0-047 - Oracle Database SQL Expert Exams exam dumps system from our company can help all customers ward off network intrusion and attacks prevent information leakage, protect user machines network security. The mission of Omgzlook is to make the valid and high quality Oracle test pdf to help you advance your skills and knowledge and get the 1Z0-047 Valid Test Discount exam certification successfully. When you visit our product page, you will find the detail information about 1Z0-047 Valid Test Discount practice test.

For example, it will note that how much time you have used to finish the 1Z0-047 Exams study guide, and how much marks you got for your practice as well as what kind of the questions and answers you are wrong with. Once you submit your practice, the system of our 1Z0-047 Exams exam quiz will automatically generate a report. The system is highly flexible, which has short reaction time.

Oracle 1Z0-047 Exams - A bold attempt is half success.

Our Oracle Database SQL Expert exam questions are designed by a reliable and reputable company and our company has rich experience in doing research about the study materials. We can make sure that all employees in our company have wide experience and advanced technologies in designing the 1Z0-047 Exams study dump. So a growing number of the people have used our study materials in the past years, and it has been a generally acknowledged fact that the quality of the 1Z0-047 Exams test guide from our company is best in the study materials market. Now we would like to share the advantages of our 1Z0-047 Exams study dump to you, we hope you can spend several minutes on reading our introduction; you will benefit a lot from it.

Using 1Z0-047 Exams real questions will not only help you clear exam with less time and money but also bring you a bright future. We are looking forward to your join.

1Z0-047 PDF DEMO:

QUESTION NO: 1
Evaluate the following CREATE SEQUENCE statement: CREATE SEQUENCE seq1 START WITH 100
INCREMENT BY 10 MAXVALUE 200 CYCLE NOCACHE; The sequence SEQ1 has generated numbers up to the maximum limit of 200. You issue the following SQL statement: SELECT seq1.nextval FROM dual; What is displayed by the SELECT statement?
A.1
B.10
C.100
D.an error
Answer:A

QUESTION NO: 2
View the Exhibit and examine the description of the EMPLOYEES table. Your company decided to give a monthly bonus of $50 to all the employees who have completed five years in the company. The following statement is written to display the LAST_NAME, DEPARTMENT_ID, and the total annual salary:
SELECT last_name, department_id, salary+50*12 "Annual Compensation" FROM employees WHERE
MONTHS_BETWEEN(SYSDATE, hire_date)/12 >= 5; When you execute the statement, the "Annual
Compensation" is not computed correctly. What changes would you make to the query to calculate the annual compensation correctly?
A.Change the SELECT clause to SELECT last_name, department_id, salary*12+50 "Annual
Compensation".
B.Change the SELECT clause to SELECT last_name, department_id, salary+(50*12) "Annual
Compensation".
C.Change the SELECT clause to SELECT last_name, department_id, (salary+50)*12 "Annual
Compensation".
D.Change the SELECT clause to SELECT last_name, department_id, (salary*12)+50 "Annual
Compensation".
Answer:C

QUESTION NO: 3
View the Exhibit and examine the description of the EMPLOYEES table. You want to display the
EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT_ID for all the employees who work in the same department and have the same manager as that of the employee having EMPLOYEE_ID 104. To accomplish the task, you execute the following SQL statement: SELECT employee_id, first_name, department_id FROM employees WHERE (manager_id, department_id) =(SELECT department_id, manager_id FROM employees WHERE employee_id = 104) AND employee_id <> 104; When you execute the statement it does not produce the desired output. What is the reason for this?
A.The WHERE clause condition in the main query is using the = comparison operator, instead of EXISTS.
B.The WHERE clause condition in the main query is using the = comparison operator, instead of the IN operator.
C.The WHERE clause condition in the main query is using the = comparison operator, instead of the =
ANY operator.
D.The columns in the WHERE clause condition of the main query and the columns selected in the subquery should be in the same order.
Answer:D

QUESTION NO: 4
View the Exhibit and examine the description of the ORDERS table. Which two WHERE clause conditions demonstrate the correct usage of conversion functions? (Choose two.)
A.WHERE order_date > TO_DATE('JUL 10 2006','MON DD YYYY')
B.WHERE TO_CHAR(order_date,'MON DD YYYY') = 'JAN 20 2003'
C.WHERE order_date > TO_CHAR(ADD_MONTHS(SYSDATE,6),'MON DD YYYY')
D.WHERE order_date IN ( TO_DATE('Oct 21 2003','Mon DD YYYY'), TO_CHAR('NOV 21 2003','Mon DD
YYYY') )
Answer:A B

QUESTION NO: 5
View the Exhibit and examine the descriptions of ORDER_ITEMS and ORDERS tables. You want to display the CUSTOMER_ID, PRODUCT_ID, and total (UNIT_PRICE multiplied by QUANTITY) for the order placed. You also want to display the subtotals for a CUSTOMER_ID as well as for a PRODUCT_ID for the last six months. Which SQL statement would you execute to get the desired output?
A.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
B.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) HAVING
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
C.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id, oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) >= 6;
D.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id WHERE MONTHS_BETWEEN(order_date, SYSDATE) <= 6
GROUP BY ROLLUP (o.customer_id, oi.product_id) ;
Answer:D

Our Microsoft SC-300 study materials can have such a high pass rate, and it is the result of step by step that all members uphold the concept of customer first. These Adobe AD0-E906 exam pdf offers you a chance to get high passing score in formal test and help you closer to your success. Microsoft DP-100 - In the process of development, it also constantly considers the different needs of users. The frequently updated of ACAMS CAMS-CN latest torrent can ensure you get the newest and latest study material. Microsoft MB-820 - Perhaps this is the beginning of your change.

Updated: May 27, 2022