312-92 Free Questions And Answers - EC Council Certified Secure Programmer V2 Valid Study Guide Files - Omgzlook

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312-92 PDF DEMO:

QUESTION NO: 1
David is an applications developer working for Dewer and Sons law firm in Los Angeles David just completed a course on writing secure code and was enlightened by all the intricacies of how code must be rewritten many times to ensure its security. David decides to go through all the applications he has written and change them to be more secure. David comes across the following snippet in one of his programs:
#include <stdio.h>
int main(int argc, char **argv)
{
int number = 5;
printf(argv[1]);
putchar( \n );
printf( number (%p) is equal to %d\n ,
&value, value);
}
What could David change, add, or delete to make this code more secure?
A. Change putchar( \n ) to putchar( %s , \n )
B. Change printf(argv[1]) to printf( %s , argv[1])
C. Change printf(argv[1]) to printf(constv [0])
D. Change int number = 5 to const number =
Answer: B

QUESTION NO: 2
Which Linux command will securely delete a file by overwriting its contents?
A. rm rf /
B. Shred
C. ps rm
D. del rm
Answer: B

QUESTION NO: 3
Shayla is designing a web-based application that will pass data to and from a company extranet. This data is very sensitive and must be protected at all costs. Shayla will use a digital certificate and a digital signature to protect the data. The digital signature she has chosen to use is based on the difficulty in computing discrete logarithms. Which digital signature has she chosen?
A. Rabin
B. Diffie-Hellman
C. SA-PSS
D. ElGamal
Answer: D

QUESTION NO: 4
Processes having the CAP_NET_BIND_SERVICE
can listen on which ports?
A. Any TCP port over 1024
B. Any UDP port under 1024
C. Any TCP port under 1024
D. Any UDP port over 1024
Answer: C

QUESTION NO: 5
After learning from an external auditor that his code was susceptible to attack, George decided to rewrite some of his code to look like the following. What is George preventing by changing the code? public voif doContent(...) {
...
String s;
if ((s = getUsernameByID( userid )) != null) {
s = StringUtils.encodeToHTML(s, 50);
response.write( <br>Applicant:<u>
+ s +
</u> );
}
...
}
A. Query string manipulation
B. XSS attack
C. Cookie poisoning
D. SQL injection
Answer: B

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Updated: May 27, 2022