OmgzlookはきみのIT夢に向かって力になりますよ。Ciscoの350-401基礎訓練の認証そんなに人気があって、Omgzlookも君の試験に合格するために全力で助けてあげて、またあなたを一年の無料なサービスの更新を提供します。明日の成功のためにOmgzlookを選らばましょう。 OmgzlookのCisco 350-401基礎訓練問題集は専門家たちが数年間で過去のデータから分析して作成されて、試験にカバーする範囲は広くて、受験生の皆様のお金と時間を節約します。我々350-401基礎訓練問題集の通過率は高いので、90％の合格率を保証します。 それほかに品質はもっと高くてCiscoの350-401基礎訓練認定試験「Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR)」の受験生が最良の選択であり、成功の最高の保障でございます。
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CCNP Enterprise 350-401基礎訓練 - Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR) Ciscoの認証資格は最近ますます人気になっていますね。 長年の努力を通じて、OmgzlookのCiscoの350-401 日本語解説集認定試験の合格率が１００パーセントになっていました。うちのCiscoの350-401 日本語解説集試験問題集は完全な無制限のダンプが含まれているから、使ったら気楽に試験に合格することができます。
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私たちの会社は、コンテンツだけでなくディスプレイ上でも、350-401基礎訓練試験材料の設計に最新の技術を採用しています。激しく変化する世界に対応し、私たちの350-401基礎訓練試験資料のガイドで、あなたの長所を発揮することができます。 また、あなたも私たちの350-401基礎訓練試験資料を使って、個人的に重要な知識を集約し、自分の需要によって、350-401基礎訓練試験のために様々な勉強方法を選ぶことができます。
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350-401 PDF DEMO:
QUESTION NO: 1
What is the correct EBGP path attribute list, ordered from most preferred to the least preferred, that the BGP best-path algorithm uses?
A. weight, local preference, AS path, MED
B. weight, AS path, local preference, MED
C. local preference, weight MED, AS path
D. local preference, weight, AS path, MED
Answer: A
Explanation:
Path Selection Attributes: Weight > Local Preference > Originate > AS Path > Origin > MED > External
> IGP Cost > eBGP Peering > Router ID
QUESTION NO: 2
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.255.255.255.254
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.1.0.0.0.0
D. Permit 10.0.0.0.0.0.0.1
Answer: B
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum:
0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a
"0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all odd- numbered hosts in the 10.0.0.0/24 subnet.
QUESTION NO: 3
Which access controls list allows only TCP traffic with a destination port range of 22-433, excluding port 80?
A. Deny tcp any any ne 80
Permit tcp any any range 22 443
B. Permit tcp any any ne 80
C. Permit tco any any range 22 443
Deny tcp any any eq 80
D. Deny tcp any any eq 80
Permit tco any any gt 21 it 444
Answer: D
QUESTION NO: 4
Which statement about multicast RPs is true?
A. RPs are required for protocol independent multicast sparse mode and dense mode.
B. By default, the RP is needed only to start new sessions with sources and receivers.
C. By default, the RP is needed periodically to maintain sessions with sources and receivers
D. RPs are required only when using protocol independent multicast dense mode.
Answer: B
Explanation:
A rendezvous point (RP) is required only in networks running Protocol Independent Multicast sparse mode (PIM-SM).
By default, the RP is needed only to start new sessions with sources and receivers.
Reference:
https://www.cisco.com/c/en/us/td/docs/ios/solutions_docs/ip_multicast/White_papers/rps.html
For your information, in PIM-SM, only network segments with active receivers that have explicitly requested multicast data will be forwarded the traffic. This method of delivering multicast data is in contrast to the PIM dense mode (PIM-DM) model. In PIM-DM, multicast traffic is initially flooded to all segments of the network. Routers that have no downstream neighbors or directly connected receivers prune back the unwanted traffic.
QUESTION NO: 5
Which statement explains why Type 1 hypervisor is considered more efficient than Type 2 hypervisor?
A. Type 1 hypervisor enables other operating systems to run on it
B. Type 1 hypervisor runs directly on the physical hardware of the host machine without relying on the underlying OS
C. Type 1 hypervisor relics on the existing OS of the host machine to access CPU, memory, storage, and network resources.
D. Type 1 hypervisor is the only type of hypervisor that supports hardware acceleration techniques
Answer: B
Explanation:
There are two types of hypervisors: type 1 and type 2 hypervisor.
In type 1 hypervisor (or native hypervisor), the hypervisor is installed directly on the physical server.
Then instances of an operating system (OS) are installed on the hypervisor. Type 1 hypervisor has direct access to the hardware resources. Therefore they are more efficient than hosted architectures.
Some examples of type 1 hypervisor are VMware vSphere/ESXi, Oracle VM Server, KVM and
Microsoft Hyper-V.
In contrast to type 1 hypervisor, a type 2 hypervisor (or hosted hypervisor) runs on top of an operating system and not the physical hardware directly. A big advantage of Type 2 hypervisors is that management console software is not required.
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Updated: May 28, 2022