350-401全真模擬試験 & Cisco Implementing Cisco Enterprise Network Core Technologies 350-401 Encor復習解答例 - Omgzlook

きみはCiscoの350-401全真模擬試験認定テストに合格するためにたくさんのルートを選択肢があります。Omgzlookは君のために良い訓練ツールを提供し、君のCisco認証試に高品質の参考資料を提供しいたします。あなたの全部な需要を満たすためにいつも頑張ります。 Omgzlookは全面的な最高のCisco 350-401全真模擬試験試験の資料を含め、きっとあなたの最良の選択だと思います。Ciscoの350-401全真模擬試験認定試験の合格証明書はあなたの仕事の上で更に一歩の昇進で生活条件が向上することが助けられます。 Omgzlookの専門家チームがCiscoの350-401全真模擬試験認証試験に対して最新の短期有効なトレーニングプログラムを研究しました。

CCNP Enterprise 350-401 きっと君に失望させないと信じています。

CCNP Enterprise 350-401全真模擬試験 - Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR) それは受験者にとって重要な情報です。 我々は受験生の皆様により高いスピードを持っているかつ効率的なサービスを提供することにずっと力を尽くしていますから、あなたが貴重な時間を節約することに助けを差し上げます。Omgzlook Ciscoの350-401 最新試験試験問題集はあなたに問題と解答に含まれている大量なテストガイドを提供しています。

OmgzlookはきみのIT夢に向かって力になりますよ。Omgzlookは多種なIT認証試験を受ける方を正確な資料を提供者でございます。弊社の無料なサンプルを遠慮なくダウンロードしてください。

その中で、Cisco 350-401全真模擬試験認定試験は最も重要な一つです。

神様は私を実力を持っている人間にして、美しい人形ではないです。IT業種を選んだ私は自分の実力を証明したのです。しかし、神様はずっと私を向上させることを要求します。Ciscoの350-401全真模擬試験試験を受けることは私の人生の挑戦の一つです。でも大丈夫です。OmgzlookのCiscoの350-401全真模擬試験試験トレーニング資料を購入しましたから。すると、Ciscoの350-401全真模擬試験試験に合格する実力を持つようになりました。 OmgzlookのCiscoの350-401全真模擬試験試験トレーニング資料を持つことは明るい未来を持つことと同じです。

まだ何を待っていますか。早速買いに行きましょう。

350-401 PDF DEMO:

QUESTION NO: 1
Which statement explains why Type 1 hypervisor is considered more efficient than Type 2 hypervisor?
A. Type 1 hypervisor enables other operating systems to run on it
B. Type 1 hypervisor runs directly on the physical hardware of the host machine without relying on the underlying OS
C. Type 1 hypervisor relics on the existing OS of the host machine to access CPU, memory, storage, and network resources.
D. Type 1 hypervisor is the only type of hypervisor that supports hardware acceleration techniques
Answer: B
Explanation:
There are two types of hypervisors: type 1 and type 2 hypervisor.
In type 1 hypervisor (or native hypervisor), the hypervisor is installed directly on the physical server.
Then instances of an operating system (OS) are installed on the hypervisor. Type 1 hypervisor has direct access to the hardware resources. Therefore they are more efficient than hosted architectures.
Some examples of type 1 hypervisor are VMware vSphere/ESXi, Oracle VM Server, KVM and
Microsoft Hyper-V.
In contrast to type 1 hypervisor, a type 2 hypervisor (or hosted hypervisor) runs on top of an operating system and not the physical hardware directly. A big advantage of Type 2 hypervisors is that management console software is not required.

QUESTION NO: 2
What is the correct EBGP path attribute list, ordered from most preferred to the least preferred, that the BGP best-path algorithm uses?
A. weight, local preference, AS path, MED
B. weight, AS path, local preference, MED
C. local preference, weight MED, AS path
D. local preference, weight, AS path, MED
Answer: A
Explanation:
Path Selection Attributes: Weight > Local Preference > Originate > AS Path > Origin > MED > External
> IGP Cost > eBGP Peering > Router ID

QUESTION NO: 3
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.255.255.255.254
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.1.0.0.0.0
D. Permit 10.0.0.0.0.0.0.1
Answer: B
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum:
0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a
"0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all odd- numbered hosts in the 10.0.0.0/24 subnet.

QUESTION NO: 4
Which access controls list allows only TCP traffic with a destination port range of 22-433, excluding port 80?
A. Deny tcp any any ne 80
Permit tcp any any range 22 443
B. Permit tcp any any ne 80
C. Permit tco any any range 22 443
Deny tcp any any eq 80
D. Deny tcp any any eq 80
Permit tco any any gt 21 it 444
Answer: D

QUESTION NO: 5
Which statement about multicast RPs is true?
A. RPs are required for protocol independent multicast sparse mode and dense mode.
B. By default, the RP is needed only to start new sessions with sources and receivers.
C. By default, the RP is needed periodically to maintain sessions with sources and receivers
D. RPs are required only when using protocol independent multicast dense mode.
Answer: B
Explanation:
A rendezvous point (RP) is required only in networks running Protocol Independent Multicast sparse mode (PIM-SM).
By default, the RP is needed only to start new sessions with sources and receivers.
Reference:
https://www.cisco.com/c/en/us/td/docs/ios/solutions_docs/ip_multicast/White_papers/rps.html
For your information, in PIM-SM, only network segments with active receivers that have explicitly requested multicast data will be forwarded the traffic. This method of delivering multicast data is in contrast to the PIM dense mode (PIM-DM) model. In PIM-DM, multicast traffic is initially flooded to all segments of the network. Routers that have no downstream neighbors or directly connected receivers prune back the unwanted traffic.

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Updated: May 28, 2022